2+3[1-2(x+3)]=-7(x+1)

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Solution for 2+3[1-2(x+3)]=-7(x+1) equation:


Simplifying
2 + 3[1 + -2(x + 3)] = -7(x + 1)

Reorder the terms:
2 + 3[1 + -2(3 + x)] = -7(x + 1)
2 + 3[1 + (3 * -2 + x * -2)] = -7(x + 1)
2 + 3[1 + (-6 + -2x)] = -7(x + 1)

Combine like terms: 1 + -6 = -5
2 + 3[-5 + -2x] = -7(x + 1)
2 + [-5 * 3 + -2x * 3] = -7(x + 1)
2 + [-15 + -6x] = -7(x + 1)

Combine like terms: 2 + -15 = -13
-13 + -6x = -7(x + 1)

Reorder the terms:
-13 + -6x = -7(1 + x)
-13 + -6x = (1 * -7 + x * -7)
-13 + -6x = (-7 + -7x)

Solving
-13 + -6x = -7 + -7x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7x' to each side of the equation.
-13 + -6x + 7x = -7 + -7x + 7x

Combine like terms: -6x + 7x = 1x
-13 + 1x = -7 + -7x + 7x

Combine like terms: -7x + 7x = 0
-13 + 1x = -7 + 0
-13 + 1x = -7

Add '13' to each side of the equation.
-13 + 13 + 1x = -7 + 13

Combine like terms: -13 + 13 = 0
0 + 1x = -7 + 13
1x = -7 + 13

Combine like terms: -7 + 13 = 6
1x = 6

Divide each side by '1'.
x = 6

Simplifying
x = 6

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